思路：单调递减栈，找「上一个比当前价格大的元素索引」。正序遍历，弹出所有 ≤ 当前价格的索引；跨度 = 当前索引 - 栈顶索引（栈空则为 当前索引 + 1）。
obtain the bucket from the number of bytes, 60 - __builtin_clzll(byte_size); (Why does this work? We use 4 bits for alignment so there cannot be
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But that only goes so far. When someone in the crowd shouted "Play the Spice Girls!", he responded with a swift riposte: "Sorry, I don't take requests."
千村千面的风土人情，决定了乡村产业要各展其长，走适合自己的振兴道路。，更多细节参见夫子
Мерц резко сменил риторику во время встречи в Китае09:25。一键获取谷歌浏览器下载对此有专业解读
Nature, Published online: 25 February 2026; doi:10.1038/s41586-026-10175-6