思路：单调递减栈，找「上一个比当前价格大的元素索引」。正序遍历，弹出所有 ≤ 当前价格的索引；跨度 = 当前索引 - 栈顶索引（栈空则为 当前索引 + 1）。
Meta 已经极其直白地交出了底牌：不再把几千亿美元的 AI 身家性命，全部押在黄仁勋的一个篮子里。当谷歌的 TPU 不再只是实验室里的屠龙刀，当 AMD 拿到了 600 亿的输血，AI 芯片赛道的真正血战，才刚刚拉开序幕。（本文首发钛媒体App , 作者｜硅谷Tech news，编辑｜秦聪慧）
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Photograph: Julian Chokkattu
，详情可参考同城约会
Homes on a street at severe risk of flooding will be bought by a local council and demolished as they remain at risk of further damage.，更多细节参见夫子
After shooting to international fame as a Russian spy in drama series The Americans, Rhys said he was often mistaken for being American and Russian because of his long list of on-screen roles.